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Factor completely 3y^4 - 2y^2 - 5

Factor completely 3y^4 - 2y^2 - 5
asked 69.6k views
4 votes
Factor completely 3y^4 - 2y^2 - 5

asked
User Amol Fasale
by
7.8k points

1 Answer

5 votes
3y^4 -2y^2 -5
(3y^2 -5)(y^2 +1)
answered
User Yoann Chambonnet
by
7.9k points
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