Question

A(n+y)=10y+32 solve for y

Answer 1

(32-an)/(a-10)

Explanation:

Answer 2

we have

`a(n+y)=10y+32`

Solve for y

`a(n+y)=10y+32\\an+ay=10y+32`

Group terms that contain the variable y, and move the other terms to the opposite side of the equation

`ay-10y=32-an\\ y(a-10)=32-an`

Divide by
`(a-10)` both sides

`y=((32-an))/((a-10))`

therefore

the answer is

`y=((32-an))/((a-10))`