Question

Write a complete set of quantum numbers for the fifth electron added to a hydrogen ion (i.e., the fifth electron in any electron configuration).

Answer 1

n=
l=
m(l)=
m(s)=

start with H^+ (no electrons) , then adding 5 electrons will be 1s2 2s2 2p1
so for the 5th electron
n = 2
l = 1
ml = -1
ms = 1/2

Answer 2

Step-by-step explanation:

In atoms, there are a total of four quantum numbers: the principal quantum number (n), the orbital angular momentum quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms).

The Hydrogen ion has no electron to begin with, so upon adding five electrons, it's electronic configuration becomes;

Is2 2s2 2p1

The principal quantum number (n) = 2 (Second energy level)

The value of l is dependent on the principal quantum number n. Unlike n, the value of l can be zero. It can also be a positive integer, but it cannot be larger than one less than the principal quantum number (n-1):

Hence, l = 2-1 = 1

The magnetic quantum number ml determines the number of orbitals and their orientation within a subshell. Since ml must range from –l to +l, then ml can be: --1, 0, or 1.

Unlike n, l, and ml, the electron spin quantum number ms does not depend on another quantum number. It designates the direction of the electron spin and may have a spin of +1/2, represented by↑, or –1/2, represented by ↓