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How many solutions are possible for the equation 5(x-3)=7x-2(x+)1

How many solutions are possible for the equation 5(x-3)=7x-2(x+)1
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How many solutions are possible for the equation 5(x-3)=7x-2(x+)1

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User William Morris
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1 Answer

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5(x-3)= 7x-2(x+)1

5x - 15 = 7x - 2x + 1

5x - 15 = 5x + 1

-5x -5x

- 15 = 1

NO SOLUTIONS because -15 is not equal to 1
answered
User Rajmohan
by
8.9k points
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