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Which electron configuration represents the electrons of an atom in an excited state

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2-8-1
Name: Sodium
Symbol: Na
Atomic Number: 11
Atomic Mass: 22.98977 amu
Melting Point: 97.72 °C (370.87 K, 207.9 °F)
Boiling Point: 883 °C (1156 K, 1621 °F)
Number of Protons/Electrons: 11
Number of Neutrons: 12
Classification: Alkali Metal
Crystal Structure: Cubic
Density @ 293 K: 0.971 g/cm3
Color: silvery

answered
User Ian Hincks
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7 votes

Answer:

See explanation.

Step-by-step explanation:

Hello,

In this case, an excited state means is referred to the valence electron that has moved from its lower state orbital, at which the lowest available energy is present, to another orbital with higher energy.

In this manner, any electron configuration in which the last electron is located at an orbital with higher energy, stands for an element at an excited state. For instance, looking at the lower state of nitrogen, the resulting electron configuration turns out:


1s^22s^22p^3

Now, by exciting the element, an electron could occupy a large number of orbitals. Nonetheless, it will occupy the next available one, as shown below:
1s^22s^22p^23s^1

Wherein the valence electron is now at the
3s orbital in the so called excited state.

Best regards.

answered
User Umesh Mishra
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