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Factor completely 3a^4y^3 − 12a^3y^2 + 6a^2y.

Factor completely 3a^4y^3 − 12a^3y^2 + 6a^2y.
asked 88.5k views
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Factor completely 3a^4y^3 − 12a^3y^2 + 6a^2y.

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User Eric Chu
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1 Answer

3 votes
the answer would be 6(2x^4y^3-6x^3y^2+x^2y)
answered
User MaVVamaldo
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