Question

The area of a rectangle is 452in2452⁢in2. if the width of the rectangle is xx inches, write a function for the perimeter, p(x)p(x) .

Answer 1

Length L of the rectangle = 452/x inches where x is the width.

Perimeter p(x) = 2 (L +x) = 2 (452/x + x)

= 2 ( 452 + x^2) / x answer