asked 116k views
5 votes
How do you solve
(x-5)^2-4(x-5)-21=0

asked
User Jmjr
by
7.7k points

1 Answer

3 votes
Let's solve your equation step by step.

(x-5)^2 -4(x - 5) - 21 = 0

Step 1: Simply both sides of the equation.

x^2 - 14x + 24=0

Step 2: Factor left side of the equation.

(x - 2)(x - 12) = 0

Step 3: Set factors equal to 0.

x - 2 = 0 or x - 12 = 0

x = 2 or x = 12

Answer:

x = 2 or x = 12


answered
User DJSunny
by
8.0k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.