A drama club sold 120 child tickets and 80 adult tickets to a play a child ticket is 3 dollars less than an adult ticket The club sold a total of 640 dollars worth of tickets What were the prices?

Answer by Don Dfoofnik
CONFIDENCE VOTES 210K
There are three kinds of answers: ones that are mostly right, ones that are mostly wrong, and those that once were right but now are wrong.
The tickets are $5 adult and $2 child.
Here is the algebraic substitution.
A = adult ticket money
C = child ticket money
120C + 80A = 640
C = A-3 (three dollars less)
120 (A-3) + 80A = 640
120 A - 360 + 80A = 640
200 A = 1000