Question

You have 43 pencils. Besides 1 group of 43 pencils, is it possible to divide the pencils into groups with the same number of pencils with no pencils left over?

Answer 1

You would not have enough pencils to equally distribute into equal piles.

You would always have a remainder.

This is because there are no two numbers that multiply and equal 43.

Accept 43 x 1 as stated in the question.

Good Luck! <3

Answer 2

No, it is not possible.

Explanation:

We have been given that you have 43 pencils. We are asked to find whether it is possible that besides 1 group of 43 pencils can we divide the pencils into groups with the same number of pencils with no pencils left over.

We know that 43 is a prime number and it has only two factors that are 1 and 43, so it is only divisible by 1 and 43.

Therefore, it is not possible to divide the pencils into groups with the same number of pencils with no pencils left over.