Question

Which point is an x-intercept of the quadratic function f(x)=(x-8)(x-9)?

Answer 1

The zeroes are (0,8) and (0,9)

Use the zero product property to find this
(x-8)=0
x=8

(x-9)=0
x=9

Answer 2

The points are (8,0) and (9, 0)

Explanation:

Given the function

`f(x)=(x-8)(x-9)`

we have to find the point which is an x-intercept of the quadratic function.

X-intercept is the x-coordinate of a point where a graph of function intersects the x-axis i.e the value of x at which the value of y is 0.

Hence, to find x-intercept we have to put the value of y=0 in f(x)

`(x-8)(x-9)=0`

Using zero product property

⇒
`(x-8)=0\text{ or }(x-9)=0`

`x=8\text{ or }x=9`

The points are (8,0) and (9, 0)