Question

An average sample of coal contains 3.0% sulfur by mass. calculate the moles of sulfur present in 2.40 ´ 103 kg of coal.

Answer 1

3.0 %S mS/mCoal 32.06 g/mole = molar mass of S Amount of coal = 2.40 x 10^3 kg (2.40 x 10 ^3 kg Coal ) x (1000g Coal/ 1 kg Coal) x (3 g S/ 100 g Coal) x(1 mole S/ 32.06 g S) = 22457.89 = 2.3 x10^4 mole S