Question

Find the perimeter of the polygon with vertices of A(0, 0), B(4, 0) and C(2, 3). Round to the nearest tenth. Just enter one number as your answer.

Answer 1

11.2

Since we have 3 vertices, we have a triangle. The sides are AB, BC, and AC. Using the Pythagoras's theorem, we can calculate the length of each side.
Side AB is from (0,0) to (4,0) = length of 4.Side AC is from (0,0) to (2,3) = sqrt(2*2+3*3) = sqrt(13) = 3.6056Side BC is from (4,0) to (2,3) = sqrt((4-2)^2 + 3*3) = sqrt(13) = 3.6056
Add together 4, 3.6056, and 3.6056 giving 11.2112. Rounding to the nearest tenth, gives 11.2