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Y=x^2+2x+1 domain and range

1 Answer

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This is the equation of a parabola. x can be any real number. domain (-∞,∞) or any real number.

The range is what y-values you can have. y values will start at the vertex and go up to infinity since it's an upward facing parabola (+a).

Vertex (-b/2a , y)
-b/2a = -2/2 =1
plug this in to find y

(-1)^2 + 2(-1) + 1 = 0

Vertex (-1, 0)

y goes from 0 to +∞
this is the range

answered
User Markussvensson
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