Question

How do you solve 3/2y = 16/y+2

Answer 1

First, multiply both sides by y to get rid of that y in the denominator.
`y((3)/(2) y)= y( (16)/(y) + 2)`

`(3)/(2)y^2= 16+2y`
Then, rearrange it to put it into standard form so you can easily see the values for a, b, and c.

`(3)/(2)y^2 +2y +16=0`
Plug into quadratic formula, and you get this result:

`y= (2+/- √(100) )/(3)`
So, y=4, y=8/3