Question

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?

Answer 1

After doing the calculations, I also got 7/11 as my answer.

Explanation:

Answer 2

add all flowers to get denominator

4+3+4=11

now add carnations and roses

3+4=7

so your answer is

7/11 chance