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When asked his age, the algebra teacher said, “if you square my age, then subtract 23 times my age, the result is 50.” how old is he?

1 Answer

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Let the age be x.

Given,


x^(2) - 23x = 50


x^(2) - 23x - 50 = 0


x^(2) - 25x + 2x - 50 = 0


x(x -25)+2(x-25)=0


(x+2)(x-25)=0

Hence, x = -2 or 25.

Since, the age of the teacher cannot be in negative, the age of the teacher is 25 years.

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User SWilk
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