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Gragh h(t) = 400 − 39t − 157e−t/4

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Gragh h(t) = 400 − 39t − 157e−t/4

asked Jun 19, 2018 64.4k views

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Gragh h(t) = 400 − 39t − 157e−t/4

Mathematics
college

by Yarin

8.5k points

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1 Answer

4 votes

The graph of
$h(t) = 400 - 39t - 157e^{ (t)/(4) }$ is attached.

Gragh h(t) = 400 − 39t − 157e−t/4-example-1

Niek answered Jun 22, 2018

by Niek

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