asked 16.5k views
1 vote
Calculate the boiling point of a 4.5 m solution of na2so4 in water (assume 100% dissociation, kb (h2o) = 0.52 °c/m)

asked
User Detilium
by
8.5k points

1 Answer

5 votes
In order to determine the change in boiling point, we use the formula:
ΔT = Kb * m * i

Where i is the van't Hoff factor. This factor is found by checking the number of ions formed when the solute is dissolved. This is:

Na₂SO₄ + water ↔ 2Na⁺ + SO₄⁻²

The number of ions formed is 3, so i = 3

ΔT = 0.52 * 4.5 * 3
ΔT = 7.02

The new boiling point is calculated using:
T = T(normal) + ΔT
T = 100 + 7.02


The new boiling point is 107.2 °C
answered
User Bhagabat Behera
by
8.2k points
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