Question

find three consecutive even integers such that the sum of the smallest integer and twice the median integer is 20more than the largest integer.

Answer 1

x = smallest; x + 2 = middle, and x + 4 = largest
x + 2(x+2) = 20 + x + 4
x + 2x + 4=24 +x
3x + 4 = 24 + x
2x = 20
x = 10
so the three integers are 10, 12, and 14