Question

How many solutions does the following equation have? ln(x2 + 4x − 5) = 0

Answer 1

alrighty
remember

`log_a(b)=c` means
`a^c=b`
and

`ln(x)=log_e(x)`
and

`x^0=1` for all real values of x
so


`ln(x^2+4x-5)=0` means

`log_e(x^2+4x-5)=0` means

`e^0=x^2+4x-5` which simplifies to
1=x²+4x-5
minus 1 both sides
0=x²+4x-6
use quadratic formula or complete the square

`x=-2+√(10)` and
`x=-2-√(10)`
2 solutions