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1/5[10-5(x-2)]=1/10(x+1)

1/5[10-5(x-2)]=1/10(x+1)
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1/5[10-5(x-2)]=1/10(x+1)

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User Fabianfett
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1 Answer

4 votes
10-5(x-2)/5=1/10(x+1)
10-5(x-2)/5=x+1/10
10(4-x)=x+1
40-10x=x+1
40=x+1+10x
40=11x+1
40-1=11x
39=11x
x=39/11
answered
User Itsjeyd
by
8.5k points
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