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2 votes
Evaluate the limit lim h → 0 (−5 + h)2 − 25/h

asked
User Vandna
by
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1 Answer

5 votes
((5+h)^2 - 25)/h
= (25 + 10h + h^2 - 25)/h
= [h(h + 10)]/h
= h + 10 => take the limit
= 10

Hope this helps
answered
User Kvothe
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8.3k points

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