Question

What is the equation of the line that passes through (-2, 4) and (4, 5)

Answer 1

y=1/6x+13/3

Explanation:

m=(y2-y1)/(x2-x1)

m=(5-4)/(4-(-2))

m=1/(4+2)

m=1/6

y-y1=m(x-x1)

y-4=1/6(x-(-2))

y-4=1/6(x+2)

y=1/6x+2/6+4

y=1/6x+1/3+4

y=1/6x+1/3+12/3

y=1/6x+13/3