Question

The perimeter of the rectangle Plainfield is 446 yards. The length of the field is 5 yards less then triple the width. What is the dimensions of the Playing field. PLEASEEEEE HELP!

Answer 1

2l+2w= 446
l= 3w-5

Use substitution
2(3w-5)+2w=446
6w-10+2w= 446
8w-10=446
8w=456
w=57

Plug this value of w in
l=3(57)-5
l=171-5
l=166

Final answer: Length=166 yds, Width= 57 yds