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Y^2(3y−4) + 7(3y−4) Factor the polynomial as the product of two binomials.

Y^2(3y−4) + 7(3y−4) Factor the polynomial as the product of two binomials.
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Y^2(3y−4) + 7(3y−4) Factor the polynomial as the product of two binomials.

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User Tidder
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2 Answers

1 vote
dur, so notice we can reverse distribute
ab+ac=a(b+c)


in this case, a=(3y-4)
so
(3y-4)y²+(3y-4)7=(3y-4)(y²+7)
answered
User Iizno
by
7.8k points
1 vote
First, factor the (3y-4) and group the remaining terms
y²(3y-4) +7 (3y-4)
(y²+7)(3y-4)
I hope this helps (:
answered
User Deepti Raghav
by
8.0k points
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