Question

X^2-6x-4=0,

First, choose the appropriate form and fill in the blanks with the correct numbers. Then, solve the equation. Round your answer to the nearest hundredth. If there is more than one solution, separate them with commas.

Answer 1

use quadratic formula since we can't factor

for 0=ax²+bx+c

`x= (-b+/-√(b^2-4ac))/(2a)`

so, for
0=1x²-6x-4
a=1
b=-6
c=-4


`x= (-(-6)+/-√((-6)^2-4(1)(-4)))/(2(1))`

`x= (6+/-√(36+16))/(2)`

`x= (6+/-√(52))/(2)`

`x= (6+/-2√(13))/(2)`

`x= 3+/-√(13)`

the solutions are x=3+√13 and x=3-√13
or aprox
x≈6.61 and x≈-0.61