Question

A waste collection tank can hold 18754 kg of methanol, which has a density of 0.788 g/cm3.

Answer 1

Given:
Mass of methanol, m = 18754 kg
Density of methanol, ρ = 0.788 g/cm³

By definition, the volume of methanol in the collection tank is
Volume = mass/density

`= ((18754 \, kg)*(10^(3) \, (g)/(kg)) )/((0.788 \, (g)/(cm^(3))) ) \\ \\ =2.38 * 10^(7) \, (g)/(cm^(3))`

Answer: 2.38 x 10⁷ g/cm³