asked 7.5k views
4 votes
HELP PLEASEEE ASAP

The y-intercept of h(x) in h(x)=x^2-16/x-4 is......

(0,4)
(0,0)
(0,-4)

asked
User FerranB
by
8.3k points

1 Answer

6 votes
h(x)=x^2-16/x-4 = [(x+4)(x-4) ] / x-4 = x + 4

y-intercept when x = 0 then y = 4
so answer is

(0,4)
answered
User HaydnD
by
8.2k points

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