How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?

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asked May 25, 2018 135k views

2 Answers

Subhas · Answer 1 · 2018-05-31T02:16:02+0000

Use ideal gas equation:

n = PV / RT

P = 100kPa = 100 x 1000 x (9.8 x 10^{-6}) = 0.98 atm
convert kPa to atm. 1 Pa = 9.8 x 10^{-6} atm
T = 293 K
V = 6.8 L
R = 1/12
put all values.
So, n = 0.272

How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?

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