Question

If the ph of a certain solution changes from 8 to 9, what happens to the hydroxide ion concentration?

Answer 1

`pH_1 = 8 \\ pH_2 = 9`


`pOH_1 = 14 - 8 = 6 \\ pOH_2 = 14 - 9 = 5`


`OH^-_1 = 10^(-6) M`


`OH^-_2 = 10^(-5) M`

Ratio =
`(10^(-5))/(10^(-6)) = 10`

so, OH- concentration will become 10 times the initial one