A number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and 1. How many solutions are possible for this situation?

Question

asked Feb 27, 2018 198k views

2 Answers

Gabriele Buondonno · Answer 1 · 2018-03-05T03:37:09+0000

we have the 2 equations:-

N = 2n + 3

N = 2(n + 1) or

N = 2n + 2

N cannot be equal to 2n + 3 AND 2n + 2.

Therefore there are no solutions.