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The isotope 206po has a half-life of 8.8 days. if you have 5.68 x 1025 atoms of this isotope, how long will it take for the sample to decay to 3.55 x 1024 atoms

1 Answer

4 votes

By using the formula

Activity final = activity initial x e ⁽₋λ x time⁾

λ = ln(2)/ half life
and,

-ln(activity final/activity initial) = .693/8.8 days x time
-ln[(3.55x10
²⁴) / (5.68x10²⁵) = .693/8.8 days x time

2.77259 = .693/8.8 days x time

2.77259 x 8.8 days = .693 x time

24.3988 = .693 x time

24.3988/.693 = time

35.2075 = time
time it will take to sample the decay is 35.2 days
answered
User MD Iyasin Arafat
by
8.5k points
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