Question

Find the solution set by using the method of equating the coefficients.

2x - 3y = 6

3x + 5y = 0

Answer 1

`\left \{ {{2x-3y=6} \atop {3x+5y=0}} \right. \\ \left \{ {{2x=6+3y} \atop {3x+5y=0}} \right. \\ \\ x=3+1,5y \\ 3(3+1,5y)+5y=0 \\ 9+ (9)/(2) y+5y=0 \\ (19)/(2) y=-9 \\ y=- (18)/(19) \\ x=3+1,5*(-(18)/(19) )= (30)/(19) \\`