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What is the center and radius of the circle with equation x2 + y2 + 6x + 16y + 64 = 0?

What is the center and radius of the circle with equation x2 + y2 + 6x + 16y + 64 = 0?
asked 34.0k views
3 votes
What is the center and radius of the circle with equation x2 + y2 + 6x + 16y + 64 = 0?

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User Prakhar Mishra
by
8.2k points

1 Answer

2 votes
Hello,

By making factors:

x^2+y^+2+6x+16y+64=0\\ x^2+6x+9+y^2+16y+64-9=0\\ (x+3)^2+(y+8)^2=9\\ radius=3


answered
User Thibault Falise
by
8.1k points
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