The length of a rectangle is 5in longer than its width. If the perimeter of the rectangle is 46in, find its area

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Jayesh Khasatiya · Answer 1 · 2018-04-30T17:54:52+0000

width = x
length = x+5

2x + 2(x+5) = 46
2x + 2x + 10 = 46
4x = 46 - 10
4x = 36
x = 36/4
x = 9 in ← width

length = x+5 = 9 + 5 = 14 in

Area = 9 * 14 = 126 in²

The length of a rectangle is 5in longer than its width. If the perimeter of the rectangle is 46in, find its area

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