Question

In an industrial arts class, each student is to construct a picture frame using a different amount of materials. John is given ft. of building material. Jane is given ft. of building material. Jose is given 3.5 ft. of material. Arrange the three pieces of material in order from shortest to longest.

ANSWER CHOICES ARE IN THE IMAGES!

Answer 1

The answer is D. 3.5,3.2,3.16...

Answer 2

Arranging the three pieces of material from shortest to longest, we have:

Jane (√10 ft) < John (16/5 ft) < Jose (3.5 ft). C

How to arrange the three pieces of material in order from shortest to longest

To arrange the three pieces of material in order from shortest to longest, compare their lengths.

John: 3 1/5 ft

Jane: √10 ft

Jose: 3.5 ft

To make a comparison, convert the mixed fraction to an improper fraction and simplify the square root value:

John: 3 1/5 ft = (3 * 5 + 1) / 5 ft = 16/5 ft = 3.2 ft

Jane: √10 ft = 3.16 ft

Jose: 3.5 ft

Now, compare the lengths:

John: 3.2

Jane: 3.16

Jose: 3.5

Therefore, arranging the three pieces of material from shortest to longest, we have:

Jane (√10 ft) < John (16/5 ft) < Jose (3.5 ft)

Complete question

In an industrial arts class, each student is to construct a picture frame using a different amount of materials. John is given 3 1/5 ft. of building material. Jane is given sqrt 10 ft. of building material. Jose is given 3.5 ft. of material. Arrange the three pieces of material in order from shortest to longest.

(sqrt = Square Root)