Question

Simplify: (sin θ − cos θ)2 − (sin θ + cos θ)2

−4sin(θ)cos(θ)

2

sin2 θ

cos2 θ

Answer 1

The answer is −2cos(θ)sin(θ)+2+sin(2θ). (sin (θ) − cos (θ))^2 − (sin (θ) + cos (θ))^2 was ur question right?

Answer 2

ill write s for sine and c for cos:

(s - c)^2 - (s + c)^2
= s^2 - 2sc + c^2 - (s^2 + 2sc + c^2
= -4sc

Its the first choice