Question

Turn 2800=1900(1+0.025)^n into a logarithm

Answer 1

`\bf \textit{exponential form of a logarithm}\\\\ log_{{ a}}{{ b}}=y \implies {{ a}}^y={{ b}}\\\\ -------------------------------\\\\ %2800=1900(1+0.025)^n into a logarithm 2800=1900(1+0.025)^n\implies \cfrac{2800}{1900}=(1.025)^n\implies \cfrac{28}{19}=1.025^n \\\\\\ \begin{cases} a=1.025\\ b=(28)/(19)\\ \end{cases}\implies log_(1.025)\left( (28)/(19) \right)=n`