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Find a function in the form of y = f(x) for the parametric equation:
x = 2t
y = t² - 6t

1 Answer

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\bf \begin{cases} x=2t\implies \cfrac{x}{2}=\boxed{t}\\\\ y=t^2-6t\\ ----------\\ y=\left( \boxed{(x)/(2)} \right)^2-6\left( \boxed{(x)/(2)} \right) \end{cases}\implies y=\cfrac{x^2}{4}-\cfrac{6x}{2} \\\\\\ y=\cfrac{x^2}{4}-3x
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User Dzada
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