asked 35.8k views
3 votes
A jar has 4 balls lettered A, E, D, and G. One ball is drawn from the jar and it's letter is noted. A second ball is also drawn without replacing the first ball and it's letter is noted. List all the possible outcomes and find the probability that the letters on the 2 balls drawn consist of at least 1 vowel, no vowels, and the same letter.

1 Answer

5 votes
Possible outcomes are AE AD AG ED EG DG
EA DA GA DE GE GD

P( at least one vowel) = 10/12 = 5/6

P( no vowels) = 2/12 = 1/6

P(same letter) = 0
answered
User Yuvraj Patil
by
9.0k points
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