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Help me please !!!!!!!!

Help me please !!!!!!!!-example-1
asked
User Milan M
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7.8k points

1 Answer

2 votes
Line up corresponding parts of the similar triangle to make ratios.
You need 3 parts of the 6, including one complete fraction.
Next cross-multiply to solve for the missing sides.

# 15
a/x = b/y = c/z
6/10 = 8/y
cross-multiply
6y = 8*10
6y = 80
divide both sides by 6
y = 13 1/3 or 40/3
CHECK
6/10 ??=?? 8/ (13 1/3)
.6 = .6 CHECKS

# 16
4/7 = c/5
cross-multiply
7c = 4 * 5
7c = 20
divide both sides by 7
c = 20/7
CHECK
4/7 ??=?? (20/7)/5
.5714 = .5714 CHECKS


answered
User PeterD
by
8.8k points

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