Question

Find the perimeter of the following shape, rounded to the nearest tenth: Shape ABCD is shown. Point A is at -3,5. Point B is at 2,6. Point C is at 0, 2. Point D is at -5, 1.

Answer 1

By turning the points into triangles and using Pythagorean theorem you can solve for the lonest side(of the triangle) which is Equal to that side.
AB [(3-2)^2]+[(6-1)^2]=square root of (1+25)=Square root of 26= 5.099
If you do this for all 4 sides and add them up you get the answer:
P(perimeter)=19.1