Question

How many moles of libr are contained in 347 g of water in a 0.175 m libr solution?

Answer 1

Molaridad = número de lunares de soluto/Kg de disolvente

La molaridad se da en el problema como 0,175 m

Masa de disolvente = 347 gm = 0,347 Kg

por lo tanto

0.175 = número de lunares de LiBr / 0.347

número de lunares de LiBr = 0,175 x 0,347 = 0,060725 lunares

Step-by-step explanation:

Answer 2

Molarity = number of moles of solute/Kg of solvent

Molarity is given in the problem as 0.175 m
Mass of solvent = 347 gm = 0.347 Kg

Therefore,
0.175 = number of moles of LiBr / 0.347
number of moles of LiBr = 0.175 x 0.347 = 0.060725 moles