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2 votes
What is the volume of 55 L of gas initially at 500 K and 4.25 atm when conditions change to STP?

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User Sverre
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1 Answer

5 votes
Answer is 127.6
(55L) X (273K) / (500) X (4.25atm) / (1.00atm)=127.6L
answered
User Bogdan Rybak
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