Question

HELP! 16x^(2)-40x+6x-15=0 I already factored and this is the extended version, but I don't know where to go from here. Show your work :)

Answer 1

If you're trying to solve for x, you need to use the quadratic formula.

`(-b+/- √(b^2 - 4(a)(c)) )/(2a)`
Plug in the numbers from the standard form of a quadratic equation
(which is
`ax^2 + bx + c = 0`)

`(34+/- √(34^2 - 4(16)(15)) )/(2(16))`
From here, this solves down to

`(34+/- √(196))/(32)`
Take the square root of 196, which is 14

`(34+/- 14)/(32)`
Now, you can solve for both the + and - variations on the equation.
The solutions to your equation are 1.5 and 5/8 (probably)