Question

How do you complete the square to rewrite y= x^ -6x + 15 in vertex form

Answer 1

Vertex form of a quadratic equation is
`y=a(x-h)^(2)+k`
where (h, k) is the vertex.

Our aim is to write the expression
`y=x^(2) -6x+15` in the form

`y=a(x-h)^(2)+k`




`y=x^(2) -6x+15`


`y=x^(2) -2*3*x+15`


`y=(x^(2) -2*3*x+ 3^(2))-3^(2)+ 15`


`y=(x-3)^(2)-9+15`


`y=(x-3)^(2)+6`