Question

Compute (x^2 + 6x - 9) ÷ (x - 3)

Answer 1

(x-3) is NOT a factor of the numerator (x^2+6x-9).
The way to get the quotient is by either long division or synthetic division, which gives the quotient as (x+9) with a remainder or 18.
In other words, the quotient is
(x+9)+18/(x-3)