Find two consecutive even integers such that the smaller added to five times the larger give you a sum of 46.

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asked Aug 3, 2018 186k views

1 Answer

Triode · Answer 1 · 2018-08-07T05:47:42+0000

First consecutive integer: n
Second consecutive integer: n + 2 (next even integer)
n + 5(n + 2) = 46
n + 5n + 10 = 46

6n + 10 = 46
6n = 36
n = 6
n + 2 = 8
Your answer is 6 and 8

Find two consecutive even integers such that the smaller added to five times the larger give you a sum of 46.

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