Question

How many moles of ions are released when 0.27 mol of cobalt (ii) chloride, cocl2, is dissolved in water?

Answer 1

CoCl₂(s) → Co²⁺(aq) + 2Cl⁻(aq)

n(CoCl₂)=0.27 mol

n(Co²⁺)=n(CoCl₂)
n(Cl⁻)=2n(CoCl₂)

n=n(Co²⁺)+n(Cl⁻)=3n(CoCl₂)

n=3*0.27=0.81 mol